A 2.0-kg solid cylinder starts from rest at the top of a ramp and rolls without slipping. Calculate its speed when it reaches the bottom of the ramp. The ramp is 0.79 m high and 5.0 m long.
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As there is no slipping,
The kinetic energy due to rotation is half of the linear kinetic energy.
M g h = 0.5 M U² + 0.5 (0.5 M R²) U² / R²
g h = 0.5* U² + 0.5*0.5 U²
9.8* 0.79 = 0.5* U² + 0.5*0.5 U²
U = 3.21 m/s
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The kinetic energy due to rotation is half of the linear kinetic energy.
M g h = 0.5 M U² + 0.5 (0.5 M R²) U² / R²
g h = 0.5* U² + 0.5*0.5 U²
9.8* 0.79 = 0.5* U² + 0.5*0.5 U²
U = 3.21 m/s
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