y = (x^2)(2x-3)^3 find dy.
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y = x² (2x - 3)³
dy/dx = 2x (2x - 3)³ + x² (3) (2x - 3)² (2)
dy/dx = 2x (2x - 3)³ + 6x² (2x - 3)²
dy/dx = (2x - 3)² (2x (2x - 3) + 6x²)
dy/dx = (2x - 3)² (4x² - 6x + 6x²)
dy/dx = (2x - 3)² (10x² - 6x)
dy/dx = 2x (2x - 3)³ + x² (3) (2x - 3)² (2)
dy/dx = 2x (2x - 3)³ + 6x² (2x - 3)²
dy/dx = (2x - 3)² (2x (2x - 3) + 6x²)
dy/dx = (2x - 3)² (4x² - 6x + 6x²)
dy/dx = (2x - 3)² (10x² - 6x)
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You mean find dy/dx
use product rule, power rule and composite rule
Or expand and find the derivative of the quintic polynomial.
Try it and take your lumps if you error, just like the rest of us.
use product rule, power rule and composite rule
Or expand and find the derivative of the quintic polynomial.
Try it and take your lumps if you error, just like the rest of us.