Algebra problem, please help!
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Algebra problem, please help!

[From: ] [author: ] [Date: 12-04-01] [Hit: ]
!!......
I am struggling with this problem:

100=3/1.025 + 103/(1+x)^2

answer is x = 3.0075

how do I solve it? Thank you for your help!

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100=3/1.025 + 103/(1+x)^2
3/1.025 + 103/(1+x)^2=100
103/(1+x)^2=100-3/1.025=100-2.9268=97.07
(1+x)^2= 103*97.07=9998.5366
1+x=+/- 99.99
x=1+/- 99.99
x= 100.99 or -98.99
You have missed some where

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How did you get the answer? Just explain it that way! I'm not gonna cheat! If you did it on a calculator that's you tough luck! Ask a friend for help!!!
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