A. 1s^2 2s^3 2p^6 3s^2
B. 1s^2 2s^2 2p^6
C. 1s^2 2s^2 2p^6 3s^2 3p^3
D. 1s^2 2s^2 2p^6 3s^1
B. 1s^2 2s^2 2p^6
C. 1s^2 2s^2 2p^6 3s^2 3p^3
D. 1s^2 2s^2 2p^6 3s^1
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Hello, Image, have a little Chem question today? Okay, you have the right person for the job. The answer
is "A". No known element can have more than two electrons in the "s" orbital, it may have one
electron or two, that is all. It does not matter if it is the first "s" shell, 1s, or the last, 7s, two electrons are
the limit. The atom will begin building from the 1s1 orbital (Hydrogen), to the 1s2 pairing (Helium), on to
the 2s orbital, then the 2p orbital (Boron), with a limit of six electrons (Neon), and I can go on and on, but
I'm sure you have the picture. If in doubt just look at any good Periodic Table, a most invaluable asset
when dealing with Chemistry.
is "A". No known element can have more than two electrons in the "s" orbital, it may have one
electron or two, that is all. It does not matter if it is the first "s" shell, 1s, or the last, 7s, two electrons are
the limit. The atom will begin building from the 1s1 orbital (Hydrogen), to the 1s2 pairing (Helium), on to
the 2s orbital, then the 2p orbital (Boron), with a limit of six electrons (Neon), and I can go on and on, but
I'm sure you have the picture. If in doubt just look at any good Periodic Table, a most invaluable asset
when dealing with Chemistry.
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The first one because 2s can only have a total of 2 electrons so it would have to be 2s2