Can you solve this problem.

A box contains oranges and grapes.
An equal number of oranges and grapes are rotten.
2/3 of all the oranges are rotten and 3/4 of all the grapes are rotten.

What fraction of all the total number of pieces of fruit in the box are rotten?

"an equal number of oranges and grapes are rotten"

(2/3)O = (3/4)G
O = (9/8)G

So the total rotten fruit is:

(2/3)O + (3/4)G
(2/3)(9/8)G + (3/4)G
(18/24)G + (18/24)G
(3/2)G

As a fraction of the total number of pieces of fruit in the box:

(3/2)G/(O + G)
(3/2)G/[(9/8)G + G]
(3/2)G/[(17/8)G]
24/34
12/17

That's a lot of bad fruit!