A highway curve has a radius of 0.14 km and is unbanked. A car weighing 12 kN goes around the curve at a speed of 24 m/s without slipping. What is the magnitude of the horizontal force of the road on the car?
a. 12 kN
b. 17 kN
c. 13 kN
d. 5.0 kN
e. 49 kN
a. 12 kN
b. 17 kN
c. 13 kN
d. 5.0 kN
e. 49 kN
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You are solving for the centriptal force, which is static friction in this case.
F = m*ac
ac = v^2/r
= 24^2/140m = 4.11
m= 12kN / 9.8m/s = 1224.5 kg
F = 1224.5*4.11 = 5038N ≈ 5kN
F = m*ac
ac = v^2/r
= 24^2/140m = 4.11
m= 12kN / 9.8m/s = 1224.5 kg
F = 1224.5*4.11 = 5038N ≈ 5kN
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Use the equation F = (MV^2)/R
F= centripetal force (the force that pulls you towards the centre of your curved path)
M= mass
V = velocity
R = Radius :)
F= centripetal force (the force that pulls you towards the centre of your curved path)
M= mass
V = velocity
R = Radius :)
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F = m*a = (W/g)*V²/R = (12000/9.8)*24²/140
F = 5.0 kN
F = 5.0 kN