Math help!!!! : / still dont get it
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Math help!!!! : / still dont get it

[From: ] [author: ] [Date: 11-11-24] [Hit: ]
so itd look like 4n^2(3n+1), make sure you put a 1 when your factor is the same thing as one of your terms because when you distribute you need to have your original equation to prove that its correct. (Distribution is where you take each term in the parentheses and multiply it by the term on the outside.Hope this helps!......
GCD OF THE TERMS OF EACH POLYNOMIAL

4c^3-8c^2+8

12n^3+4n^2

8x^3-12x

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I think what you're looking for is a greatest common factor. To do this, you need to find out what each term in the polynomial has in common with everything else. So 4c^3-8c^2+8 all have a 4 in common. So when you take out a 4 you're left with c^3-2c^2+2. and to properly write this as a factor it'd be
4(c^3-c^2+2). for the second polynomial your common factor is 4n^2 because both of the terms contain an n^2 and a multiple of 4. so it'd look like 4n^2(3n+1), make sure you put a 1 when your factor is the same thing as one of your terms because when you distribute you need to have your original equation to prove that it's correct. (Distribution is where you take each term in the parentheses and multiply it by the term on the outside.) so the last one is going to be 4x(2x^2-3)
Hope this helps!

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4 (c³ - 2c² + 2)

4n² (3n + 1)

4x (2x² - 3)
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