The product of three consecutive whole numbers is 999900. What is the smallest of the three numbers
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The product of three consecutive whole numbers is 999900. What is the smallest of the three numbers

[From: ] [author: ] [Date: 11-11-24] [Hit: ]
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99

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x(x + 1)(x + 2) = 999900

x(x^2 + 3x + 2) = 999900

x^3 + 3x^2 + 2x - 999900 = 0

solve to find your real integer solution
1
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