Angular velocity around a circle
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Angular velocity around a circle

[From: ] [author: ] [Date: 11-11-12] [Hit: ]
80rad/s/s x 6.and then the linear velocity = this value of w x 3.......
2 objects are initially π/4 apart about ɵ = 0 in a circle that has a radius of 3.33m. Object A at ɵ= π/4 moves with a constant speed of 2.50 radian/second. Object B at ɵ = 0 accelerates starting from rest at 0.80 radian/second^2. Both objects travel in the counter clockwise direction.

I figured out the time they both will meet in the circle as being 6.83 seconds.

Kind of stumped on how to find the velocity of object B when it meets object A.

How do I use the radius that is given to solve it?

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the linear velocity of an object is related to angular velocity by

v = w r where w is the angular velocity and r is the radius

if you know the time of interest = 6.83s, then you know the angular velocity of B at that time is

w = w0+ alpha t = 0 + 0.80rad/s/s x 6.83s

and then the linear velocity = this value of w x 3.33m
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