"Find the exact area of the surface obtained by rotating the curve about the x axis" The problem is Y = x^3, from the bounds o
I use the equation 2pi*y*ds
I get stuck in the middle of the problem, so i try to integrate this which I get from plugging in and simplifying the above equation: 2pi x^3 * (16+ x^6)^(1/2)
And, stuck. The square root throws me, I don't know how to get rid of it to integrate
I use the equation 2pi*y*ds
I get stuck in the middle of the problem, so i try to integrate this which I get from plugging in and simplifying the above equation: 2pi x^3 * (16+ x^6)^(1/2)
And, stuck. The square root throws me, I don't know how to get rid of it to integrate
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that is because you are in error on " ds " ...2π radius arc length is
int over x in [ 0 , 2 ] of { 2π x^3 √ ( 1 + 9 x^4) dx}...with w = 1 + 9 x^4
int over x in [ 0 , 2 ] of { 2π x^3 √ ( 1 + 9 x^4) dx}...with w = 1 + 9 x^4