On a frictionless horizontal air table, puck A (with mass 0.251 kg) is moving toward puck B (with mass 0.367kg ), which is initially at rest. After the collision, puck A has velocity 0.120 m/s to the left, and puck B has velocity 0.652m/s to the right.
I found the speed of Puck A before the collison to be 0.833 m/s
Calculate, the change in the total kinetic energy of the system that occurs during the collision.
I found the speed of Puck A before the collison to be 0.833 m/s
Calculate, the change in the total kinetic energy of the system that occurs during the collision.
-
compute TOTAL KE before collision
which is just A's KE = 1/2(0.251)(0.833)² = _______ J {before}
then
compute TOTAL KE after collision which is:
TOTAL KE after = (0.5)(0.251)(0.120)² + (0.5)(0.367)(0.652)² = _______ J {after}
and
subtract to find the difference ANS
since KE is NOT a vector "simple math" will solves this
which is just A's KE = 1/2(0.251)(0.833)² = _______ J {before}
then
compute TOTAL KE after collision which is:
TOTAL KE after = (0.5)(0.251)(0.120)² + (0.5)(0.367)(0.652)² = _______ J {after}
and
subtract to find the difference ANS
since KE is NOT a vector "simple math" will solves this