Add these basic vectors
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Add these basic vectors

[From: ] [author: ] [Date: 11-10-17] [Hit: ]
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An acceleration of 10m/s² up and an acceleration of 2m/s² horizontal. Thanks.

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kuiperbelt2003 has given correct answer,

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the magnitude of the resultant is found using the pythagorean theorem

resultant = sqrt[10^2+2^2] = 10.2m/s/s

the direction of the new vector is found from tan(theta) = 10/2 or theta = 78.7 deg counterclockwise up from the positive x axis

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a = sqrt (10^2 + 2^2) = sqrt(104) <<<<<

theta = tan-1 (10/2) = tan-1(5) <<<<<<,
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