I need three fractions with different dinominators that add up to 1, for example 1/2 + 1/3 + 1/6. but i need other ones!!!!!
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1/10 + 2/5 + 1/2
1/14 + 3/7 + 1/2
1/18 + 4/9 + 1/2
...
1/198 + 49/99 + 1/2
If you see the pattern, you can take an odd number denominator fraction slightly less than 1/2 + 1/2 and then 1 / (twice your odd number denominator) and this will generally give you a working solution...
1/14 + 3/7 + 1/2
1/18 + 4/9 + 1/2
...
1/198 + 49/99 + 1/2
If you see the pattern, you can take an odd number denominator fraction slightly less than 1/2 + 1/2 and then 1 / (twice your odd number denominator) and this will generally give you a working solution...
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= 1 - 1/2 - 1/3
= (6 - 3 - 2)/6
= 1/6
Answer: 1/2 + 1/3 + 1/6
= 1 - 1/3- 1/4
= (12 - 4 - 3)/12
= 5/12
Answer: 1/2 + 1/5 + 5/12
= 1 - 1/3 - 1/5
= (15 - 5 - 3)/15
= 7/15
Answer: 1/3 + 1/5 + 7/15
= (6 - 3 - 2)/6
= 1/6
Answer: 1/2 + 1/3 + 1/6
= 1 - 1/3- 1/4
= (12 - 4 - 3)/12
= 5/12
Answer: 1/2 + 1/5 + 5/12
= 1 - 1/3 - 1/5
= (15 - 5 - 3)/15
= 7/15
Answer: 1/3 + 1/5 + 7/15
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3/5 + 1/5 + 1/5
3/5 + 1/10 + 3/10
EDIT:
Jimmy - 1/4 + 1/4 + 4/5 doesn't equal to 1 (I think you had a typo)
3/5 + 1/10 + 3/10
EDIT:
Jimmy - 1/4 + 1/4 + 4/5 doesn't equal to 1 (I think you had a typo)
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1/a, 1/b and 1-[(1/a)+(1/b)] where a and b are nonzero integers.
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1/3 +1/3+1/3
1/4+1/4+1/2
1/6+1/6+2/3
1/12+1/12+5/6
1/4+1/4+4/5
1/7+1/7+5/7
theres alot more.
1/4+1/4+1/2
1/6+1/6+2/3
1/12+1/12+5/6
1/4+1/4+4/5
1/7+1/7+5/7
theres alot more.
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1/4 1/4 1/2.
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1/2+1/5+3/10