How many liters of a 60% acid solution must be added to 14 liters of a 10% acid solution to produce a 25% acid solution?
Please explain the steps so I can learn, thank you!
Please explain the steps so I can learn, thank you!
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Let x = amt of 60% acid and y = amt of 10% acid
0.6x + (0.1)14 = 0.25(x + 14)
0.6x + 1.4 = 0.25x + 3.5
0.35x = 2.1
x = 6
6 L of the 60% solution must be added.
0.6x + (0.1)14 = 0.25(x + 14)
0.6x + 1.4 = 0.25x + 3.5
0.35x = 2.1
x = 6
6 L of the 60% solution must be added.