A .06 kg tennis ball traveling at 30 m/s strikes a wall and rebounds in the opposite direction with 81% of its initial kinetic energy.
A clearly written formula (with labels) to solve this question would be enough, no need to fully solve the answers, i can calculate it using your help!
A clearly written formula (with labels) to solve this question would be enough, no need to fully solve the answers, i can calculate it using your help!
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Hello
the initial kinetic energy is
1/2*mv^2 = 1/2*0.06*30^2 = 27 Nm
81% = 21.87 Nm
the velocity is
v = √(21.87*2/0.06)
v = 27 m/s
the initial momentum is m*v = 0.06kg*30 m/s = 1.8 kgm/s
the final momentum is m*v = 0.06*kg (-27) m/s = - 1.62 kgm/s (- v, because direction is opposite)
impulse is the change of momentum = - 1.62 - 1.8 kgm/s = 3.42 kgm/s <-- ans.
Regards
the initial kinetic energy is
1/2*mv^2 = 1/2*0.06*30^2 = 27 Nm
81% = 21.87 Nm
the velocity is
v = √(21.87*2/0.06)
v = 27 m/s
the initial momentum is m*v = 0.06kg*30 m/s = 1.8 kgm/s
the final momentum is m*v = 0.06*kg (-27) m/s = - 1.62 kgm/s (- v, because direction is opposite)
impulse is the change of momentum = - 1.62 - 1.8 kgm/s = 3.42 kgm/s <-- ans.
Regards