What is the magnitude of the impulse on the ball
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What is the magnitude of the impulse on the ball

[From: ] [author: ] [Date: 11-10-17] [Hit: ]
62 kgm/s (- v,impulse is the change of momentum = - 1.62 - 1.8 kgm/s = 3.......
A .06 kg tennis ball traveling at 30 m/s strikes a wall and rebounds in the opposite direction with 81% of its initial kinetic energy.

A clearly written formula (with labels) to solve this question would be enough, no need to fully solve the answers, i can calculate it using your help!

-
Hello

the initial kinetic energy is
1/2*mv^2 = 1/2*0.06*30^2 = 27 Nm
81% = 21.87 Nm
the velocity is
v = √(21.87*2/0.06)
v = 27 m/s

the initial momentum is m*v = 0.06kg*30 m/s = 1.8 kgm/s
the final momentum is m*v = 0.06*kg (-27) m/s = - 1.62 kgm/s (- v, because direction is opposite)

impulse is the change of momentum = - 1.62 - 1.8 kgm/s = 3.42 kgm/s <-- ans.

Regards
1
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