What is the limit as x goes to infinity of A/(1+Be^(-kt)) where A, B, and k are constants
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What is the limit as x goes to infinity of A/(1+Be^(-kt)) where A, B, and k are constants

[From: ] [author: ] [Date: 11-10-17] [Hit: ]
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I know the limit as x goes to negative infinity is 0 and I thought it was 0 for positive infinity too, but it's not. Can you point me in the right direction? Thanks!

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A/(1+Be^(-kt))
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