Physics integration of Work function...my method doesn't seem to work
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Physics integration of Work function...my method doesn't seem to work

[From: ] [author: ] [Date: 11-10-17] [Hit: ]
I then divided by 100 to get meters. My answer, .0875 is wrong.I know for sure that the answer is .# (point something,......
The graph below specifies a functional relationship between the two variables u and v. The tick marks on the x axis are 2 cm/mark and the tick marks on the y axis are 1 N/mark.
Link to graph:
http://www.webassign.net/serpse/p7-27.gi…

MY ATTEMPT:

I turned the function into an equation using units of 1 for x and y (multiply later)-> 5/4x-2.25
I then used the integration function on my calculator to find the net area from a-b, b being 5 and a being 1. I then multiplied by 2 because the number I was given in the problem makes each square an area of two. I then divided by 100 to get meters. My answer, .0875 is wrong. I know for sure that the answer is .# (point something, a decimal)

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it should be in your book
1
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