Physics HELP! PLEASE HELP!!!
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Physics HELP! PLEASE HELP!!!

[From: ] [author: ] [Date: 11-09-22] [Hit: ]
220http://www.scribd.......
From eqn III )

i) Vf = Vi + g * t
0 = 32 - 10 * t
t = 0.32 seconds ( 320 milliSeconds)

ii) DeltaY= H = Vi * t + 0.5 * 9.8 * 0.32 ^ 2
H = 9.73 m

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Question 4: Is not too clear ,However , if Maxima displacement is required apply eqn II :


Vi = 1000 m/s
Vf =0
H =?
g = -10 m/s^2

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Question 5:

Finding displacement from point of release :

Apply eqn I)

H1= -10 +0.5(-10)(10)^2
= 510 m

Note Vi = -1m/s (1 m/s downwards) reason is for the defination of displacement
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Man I don't remember any of this crap from last year.....the only thing I can tell you is that acceleration due to gravity is 9.08 m/s^2


And if these problems happen to come out of the Holt Physics Workbook....the answers and work for everything starts around pg. 220
http://www.scribd.com/doc/26978901/Holt-…
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