A proton initially has V = (18)i + (5.6)j + (14)k and then 3.7 s later has V = (-15)i + (5.6)j + (15)k (in meters per second). (a) For that 3.7 s, what is the proton's average acceleration in unit vector notation, (b) in magnitude?
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acceleration is change in velocity/time; delta v = vfinal - v initial, so here:
acceleration = (-33 i +0 j +1 k)/3.7s
the magnitude = sqrt[(-33/3.7)^2 +(1/3.7)^2]
calculate these and you are done
acceleration = (-33 i +0 j +1 k)/3.7s
the magnitude = sqrt[(-33/3.7)^2 +(1/3.7)^2]
calculate these and you are done