Physics question with a parachutist

A parachutist loses one of her shoes at an altitude of 50 m while descending at a constant speed of 10 m/s. Neglecting air resistance for the shoe:

1) How long does it take for the shoe to hit the ground?

∆x = 50 m
acceleration = 0 m/s^2, because it's descending at a constant speed... right? or is it acceleration due to gravity?
Vi = 10 m/s because it fell off the moving person?
Vf = unknown
time = solving for


2) How fast is the shoe going when it hits the ground?
I can solve this once I figure out 1.


3) How long after the shoe its the ground does the parachutist land?
This totally confuses me. The first part says that she is descending at a constant speed of 10 m/s, so no matter what, she should hit the ground before or at the same time as the shoe. Do I need to calculate it with acceleration due to gravity, 10 m/s^2?

Thank you!

1)
0 = 50 - Vi*t - ½g*t²---Solve for t = 2.33 sec

2) V = Vi + g*t = 10 + 9.8*t = 32.8 m/s downward

3) tp = D/Vi = 50/10 = 5 sec; 5 - 2.33 = 2.67 sec after the shoe

Think about it; if you were 50 m above the ground descending at a constant speed and dropped your shoe, would you expect to be on the ground before it???? At t = 0, the shoe and you have the same velocity. After, the shoe accelerates away from you due to gravity, no matter how fast your initial speed.

1) a = 9.81, the parachutist is going at a constant speed because the air resistance is neglecting the force of gravity, once the shoe leaves we say that AR = 0, so a = g = 9.81 m/s^2


3) A = parachutist, 10m/s distance = 50m, you cant figure out the time it takes for the parachutist to land then subtract the difference in time?