Here's the question:
Find PQ for P (2,7) and Q (-4,2). Round to the nearest tenth.
It's multiple choice so:
6, 5.4 , 7.8, -7.8
I'm confused I don't even know how to do this?? Thanks! Explain it to if you can thanks
Also here's an extra: the measure of the supplement (two angles with measures that have a sum of 180) of an angle is 30 less than four times the measure of the complement (2 angles with measures that have a sum of 90) of the angle. Find the measure of that angle:
Multiple choice: 130, 6, 40, 50.
I thought it was gonna be like...
90x4 = 360
360-30= 330
330- 180 = 150 < but 150 isn't a choice so please help?
Find PQ for P (2,7) and Q (-4,2). Round to the nearest tenth.
It's multiple choice so:
6, 5.4 , 7.8, -7.8
I'm confused I don't even know how to do this?? Thanks! Explain it to if you can thanks
Also here's an extra: the measure of the supplement (two angles with measures that have a sum of 180) of an angle is 30 less than four times the measure of the complement (2 angles with measures that have a sum of 90) of the angle. Find the measure of that angle:
Multiple choice: 130, 6, 40, 50.
I thought it was gonna be like...
90x4 = 360
360-30= 330
330- 180 = 150 < but 150 isn't a choice so please help?
-
Plot the points. PQ can be viewed as the hypotenuse of a right triangle with sides 5 and 6. The Pythagorean formula gives the length.
a² + b² = c²
5² + 6² = c²
25 + 36 = c²
61 = c²
c = 7.8
Let the supplement and complement of A be S and C, respectively.
A + S = 180
A + C = 90
S = 4C - 30
Solve second equation for C.
C = 90 - A
Substitute into third equation.
S = 4(90 - A) - 30
Plug that into first equation.
A + 4(90 - A) - 30 = 180
Simplify.
A + 360 - 4A - 30 = 180
330 - 3A = 180
- 3A = - 150
A = 50
a² + b² = c²
5² + 6² = c²
25 + 36 = c²
61 = c²
c = 7.8
Let the supplement and complement of A be S and C, respectively.
A + S = 180
A + C = 90
S = 4C - 30
Solve second equation for C.
C = 90 - A
Substitute into third equation.
S = 4(90 - A) - 30
Plug that into first equation.
A + 4(90 - A) - 30 = 180
Simplify.
A + 360 - 4A - 30 = 180
330 - 3A = 180
- 3A = - 150
A = 50
-
distance² = (-4 - 2)² + (2 - 7)²
= (-6)² + (-5)²
= 36 + 25
= 61
distance = √61
= (-6)² + (-5)²
= 36 + 25
= 61
distance = √61