A ball is thrown vertically upwards from a point of 1.5m above the ground, with an initial velocity of 30m/s

1) Time taken for ball to hit ground?
2) How fast is ball moving when it hits the ground?
3) Total distance moved by the ball?

Any tips or equations needed are greatly appreciated. Thanks in advance.

Well the diagram U make of this situation will help solve it.
The time ball takes to rise to its max height from
the release point (1.5 m above ground) = T
T = Vo/g = 30/9.8 = 3.06 s
The time ball takes to fall from its max height to release point = T
The max height ball reaches = h = 1/2gT² = (0.5)(9.8)(3.06)² = 45.9 m
The TOTAL distance ball travels = 2(45.9) + 1.5 = 93.3 m ANS 3)
The speed ball has as Free-Falls past release point = 30 m/s, so
d = Vo(t) + 1/2gt² {where Vo = 30, g = 9.8, t = time to travel last 1.5 m)
1.5 = 30t + 4.9t²
0 = 4.9t² + 30t - 1.5 {solve quadratic for positive root of "t"}
t = 0.05 s
TOTAL time taken of in air travel by ball = 2T + t = (2)(3.06) + 0.05 = 3.11 s ANS 1)
Final speed of ball = Vo + gt = 30 + 9.8(0.05) = 30.5 m/s ANS 2)