to play a lottery game, you choose six different numbers between 1 and 40.
show that the probability of choosing all six numbers correctly is about 1 in4 million
please show me how you get the answe
(2m+1)^2-(2n+1)^2
(4m^2+4m+1)-(4n^2+4n+1)
4m^2+4m-4n^2-4n
4[m^2+m-n^2-n]
4[(m+1)m-(n+1)n]
either m or (m+1) is even same with n difference of even is even even times 4 is multiple of 8-Or you could n
E.g. convert the minutes segment to a value in between 1-10 not 1-6.
Thanks for your help.-25 minutes is 25/60
when we shorten it we get
5/12
as we cannot get too precise answer we get
0.41(6)
in minu
Heres the question -
A bag contains (n=7) balls. n are yellow, 7 are white. John will take a ball from the bag. He will look at its colour and then put it back.
1) write an expression, in temrs of
The line y=2x-3 meets the x-axis at the point P, and the line 3y+4x=8 meets the x-axis at the point Q. The two lines intersect at the point R.
find the coordinates of R
i really dont know how to do
Let f(x) =-2x^2+x -5
b)Find[ f(x+h)-f(x)]/ h, h is not equal to 0
can someone please help me understand how to go about solving this problem. id really appreciate it. thanks!-[-2(x^2+2xh+h^2) + (x+h)
Reverse Percentages
These following products have gone through 17.5% VAT, find out how much they cost before that?
Camera - £223.25
Heater - £70.50
Printer - £82.25
Computer - £2115
Dishwasher - £29
My results is not correct.-16^(log₄x) = 4
(2^4)^(log₄x) = 2^2
2^(4 log₄x) = 2^2
4 log₄x = 2
log₄x = 1/2
4^log₄x = 4^(1/2)
x = 2
Note that x = -2 is not a valid answer, since you cant have log of neg
How do you go about solving an equation when there are unknown exponents on both sides of the equation? The unknown exponent Im calling n and it will be the same value on both sides. My equation goes
number theory is harder.
only 6 people really understand it
and they cant agree with each other.-try compressible supersonic mixed gas analysis!-No...
However, it IS tricky and a pain in the proverb
I have a project for school that I need to finish, and I cant think of anything to use for my project. Anyone have any ideas? Also, it cant be school-work related.-as a low ranking thug in the local m
I will thank you so much for this help!-if a^n=b then b^(1/n)=a
(sqrt(3)^2)^2=9
sqrt(3)^4=9
sqrt(3)=9^(1/4) taking log base 9
log(base 9)(sqrt(3))=1/4=.25-There are no variables so we could simplify.
x = y^2 - 2-y= +-sq. rt. (x+2)
(Y is equal to the positive or negative square root of the quantity x+2.)
Work:x=y^2-2
+2+2x+2=y^2
(sq. rt.) (sq. rt.)
+-sq. rt. (x+2)=y
In order to solve for a variab
Please Use the factoring to solve the quadratic equation(two possible answers)
15x^2+24=0
Please explain so I can learn and thank you!-I guess your question got problem, should be 15x^2-24=0
15x^2-