x = y^2 - 2
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y= +-sq. rt. (x+2)
("Y" is equal to the positive or negative square root of the quantity "x+2".)
Work:
x = y^2-2
+2 +2
x+2 = y^2
(sq. rt.) (sq. rt.)
+-sq. rt. (x+2)=y
In order to solve for a variable in an equation, you must "undo" the steps, or reverse whatever steps were done to the variable you want to solve.
The reason why the answer is the positive OR NEGATIVE square root of (x+2) is because a negative x negative= positive (just as a positive x positive= positive). (-y)^2=(y)^2. Therefore, the square root could be pos. or neg., resulting in the same value for y.
("Y" is equal to the positive or negative square root of the quantity "x+2".)
Work:
x = y^2-2
+2 +2
x+2 = y^2
(sq. rt.) (sq. rt.)
+-sq. rt. (x+2)=y
In order to solve for a variable in an equation, you must "undo" the steps, or reverse whatever steps were done to the variable you want to solve.
The reason why the answer is the positive OR NEGATIVE square root of (x+2) is because a negative x negative= positive (just as a positive x positive= positive). (-y)^2=(y)^2. Therefore, the square root could be pos. or neg., resulting in the same value for y.
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u need another equation that equals to x and plug the twon into each other to solve for y
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You do not have enough information there to answer the question. You need another equation with x. But it might my y2=x+2
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y^2=x+2
y=±√(x+2)
y=±√(x+2)
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y²=x+2
y=±√(x+2)
y=±√(x+2)