to play a lottery game, you choose six different numbers between 1 and 40.
show that the probability of choosing all six numbers correctly is about 1 in 4 million
please show me how you get the answer
thank you
show that the probability of choosing all six numbers correctly is about 1 in 4 million
please show me how you get the answer
thank you
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You use the binomial theorem, nCr. Read as n Choose r, in this case you pick 6 from 40. You can use a calculator with an nCr function, or calculate it yourself using the factorial formula:
P = nCr = (n!)/(r!*(n-r)!) = (40!)/(6!*34!) = 3838380 (very close to 4 million).
In case you don't know what ! means, it means factorial. So
3! = 3 x 2 x 1 = 6
8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 40320
etc
P = nCr = (n!)/(r!*(n-r)!) = (40!)/(6!*34!) = 3838380 (very close to 4 million).
In case you don't know what ! means, it means factorial. So
3! = 3 x 2 x 1 = 6
8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 40320
etc
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p (any number) = 1/40
therefore you want to times 1/40 by itself 6 times to get =
This = 1/2.4414x10^+10
so that's 1
24414000000
which is about 1 in 4 million! :)
therefore you want to times 1/40 by itself 6 times to get =
This = 1/2.4414x10^+10
so that's 1
24414000000
which is about 1 in 4 million! :)