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Algebra 1 help (step by step please)

Hi I need some help w/ these algebra 1 problems. Can you give me the answers and show work/step by step way to solve them. Ok heres the problems- 1) Use substitution to solve the linear system. 3x-y=

What is the solution(s) to this equation

y*2-8y+21=6-You mean to ask What is/are the solution/s to this equation? y^2 - 8y + 21 = 6 y^2 - 8y + 15 = 0 (y - 5)(y - 3) = 0 y = 5 or y = 3-im assuming you meant to make it a quadratic equation, s

Integral question: acceleration

The acceleration of an object moving along the x-axis is given by a(t)=18t-2, where the velocity is 12 when t=2 and the position is 2 when t=1. The position x(t) =-Okay, if the position is defined to

What's the integral of 12x/(x^2+1)

Whats the integral of 12x/(x^2+1)?-∫ 12x/(x² + 1) dx Let u = x² + 1. Then, du/dx = 2x dx du = 2x dx So: ∫ (2x dx)6/u = ∫ 6/u du = 6 ∫ 1/u du Finally, we obtain: 6ln|u| + c = 6ln(x² + 1) + c I h

Determine whether the points A(-2,-1) B(2,-2) C(1, -4) are the vertices of an scalene, isosceles, or equilater

I am assuming that the question reads: Determine whether the points A(-2, -1) B(2, -2) C(1, -4) are the vertices of an scalene, isosceles, or equilateral triangle. By the Distance Formula, we see tha

Logarithmic Equations (Gr. 12)

Solve log(2x+10) = 2 The answer is x = 45 but for some reason I got a different answer and I dont know what Im doing wrong :S This is what I did: log(2x+10) = 2 10^log(2x+10 = 10^2 2x+10 = 2 x = -

What is the intersection of these two equations

326. 2y^2 = x^2 - 2 and xy = 2 I solved for y in the second equation and got y = 2/x. Then I substituted that into the first and got... a bunch of craziness! I know I gotta solve and substitute, but

Please help with trig

If sin A = 3/5 and cos B = 24/25 and both angles a and b are in Quadrant I, what is the exact value of cos (A-B) The choices are: 1) 3/5 2) 4/5 3) 44/125 4) 117/125 I cant figure this out for the li

How do I solve 16(1/2)^x/5=2

In words it is 16 times 1/2 to the x divided by five power equals two.-16(1/2)^(x/5) = 2 16(2^-1)^(x/5) = 2 16(2)^(-x/5) = 2 (2^4)(2)^(-x/5) = 2 (2)^(4-x/5) = 2 Take the log base 2 of each side (4-x/

How to I solve this exponent problem

5^x=125 Lets say I didnt know off the top of my head that 5^3=125, how would I set it up to solve x and get 3 ? Thanks!-xlog5 =log125so x= (log125)/(log5) =3...................method 1 5^X =5^3equati

Really hard calculus question

An object is dropped from a height of 400ft. (a) Find the velocity of the object as a function of time. (neglect air resistance) I think its t=400/v is that right?? (b) Use the result in (a) to find

Find the zeros of the function. :)

1) y = x^2 - 11x + 18-1)Set y equal to 0: 0=x^2-11x+18 Now foil the equation: 0 = (x-9) * (x-2) Set each part of that equation equal to 0: x-9 = 0 x=9 AND x-2=0 x=2 The zeros of the function are x

2/a+3 - 3/2a+6 + a+2/a^2+6a+9

A.) -2/a(a^2+6a+9) B.) 3a+7/2a^2+12a+18 C.)9a+25/2(a+3)^2 Which answer best fits-First thing to note is that question is incorrect and SHOULD be shown as :- 2 / ( a + 3 ) - 3 / ( 2a + 6 ) + ( a + 2

How do you do this double integral....2xe^(3xy) dxdy

evaluate the integral (2xe^(3xy) dxdy) over the rectangle A = {(x,y): 0≤x≤1, 0≤y≤2}.-∫∫A 2x e^(3xy) dA = ∫(x = 0 to 1) ∫(y = 0 to 2) 2x e^(3xy) dy dx = ∫(x = 0 to 1) (2/3) e^(3xy) {for y = 0 to 2} dx

Let C represent a parabolic arc from the point (3, -3, 2) to (4, 1, 5) and

Let C represent a parabolic arc from the point (3, -3, 2) to (4, 1, 5) and F(x, y, z) = [x/(x^2 + y^2 + z^2)] i + [y/(x^2 + y^2 + z^2)] j + [z/(x^2 + y^2 + z^2)] k. Given this information, evaluate ∫
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