Hi I need some help w/ these algebra 1 problems. Can you give me the answers and show work/step by step way to solve them. Ok heres the problems-
1) Use substitution to solve the linear system.
3x-y=
y*2-8y+21=6-You mean to ask What is/are the solution/s to this equation?
y^2 - 8y + 21 = 6
y^2 - 8y + 15 = 0
(y - 5)(y - 3) = 0
y = 5 or y = 3-im assuming you meant to make it a quadratic equation, s
The acceleration of an object moving along the x-axis is given by a(t)=18t-2, where the velocity is 12 when t=2 and the position is 2 when t=1. The position x(t) =-Okay, if the position is defined to
Whats the integral of 12x/(x^2+1)?-∫ 12x/(x² + 1) dx
Let u = x² + 1. Then,
du/dx = 2x dx
du = 2x dx
So:
∫ (2x dx)6/u
= ∫ 6/u du
= 6 ∫ 1/u du
Finally, we obtain:
6ln|u| + c
= 6ln(x² + 1) + c
I h
I am assuming that the question reads:
Determine whether the points A(-2, -1) B(2, -2) C(1, -4) are the vertices of an scalene, isosceles, or equilateral triangle.
By the Distance Formula, we see tha
Solve log(2x+10) = 2
The answer is x = 45 but for some reason I got a different answer and I dont know what Im doing wrong :S
This is what I did:
log(2x+10) = 2
10^log(2x+10 = 10^2
2x+10 = 2
x = -
326. 2y^2 = x^2 - 2 and xy = 2
I solved for y in the second equation and got y = 2/x.
Then I substituted that into the first and got... a bunch of craziness! I know I gotta solve and substitute, but
If sin A = 3/5 and cos B = 24/25 and both angles a and b are in Quadrant I, what is the exact value of cos (A-B)
The choices are:
1) 3/5
2) 4/5
3) 44/125
4) 117/125
I cant figure this out for the li
In words it is 16 times 1/2 to the x divided by five power equals two.-16(1/2)^(x/5) = 2
16(2^-1)^(x/5) = 2
16(2)^(-x/5) = 2
(2^4)(2)^(-x/5) = 2
(2)^(4-x/5) = 2
Take the log base 2 of each side
(4-x/
5^x=125
Lets say I didnt know off the top of my head that 5^3=125, how would I set it up to solve x and get 3 ? Thanks!-xlog5 =log125so x= (log125)/(log5) =3...................method 1
5^X =5^3equati
An object is dropped from a height of 400ft.
(a) Find the velocity of the object as a function of time. (neglect air resistance) I think its t=400/v is that right??
(b) Use the result in (a) to find
1) y = x^2 - 11x + 18-1)Set y equal to 0:
0=x^2-11x+18
Now foil the equation:
0 = (x-9) * (x-2)
Set each part of that equation equal to 0:
x-9 = 0
x=9
AND
x-2=0
x=2
The zeros of the function are x
A.) -2/a(a^2+6a+9)
B.) 3a+7/2a^2+12a+18
C.)9a+25/2(a+3)^2
Which answer best fits-First thing to note is that question is incorrect and SHOULD be shown as :-
2 / ( a + 3 ) - 3 / ( 2a + 6 ) + ( a + 2
evaluate the integral (2xe^(3xy) dxdy) over the rectangle A = {(x,y): 0≤x≤1, 0≤y≤2}.-∫∫A 2x e^(3xy) dA
= ∫(x = 0 to 1) ∫(y = 0 to 2) 2x e^(3xy) dy dx
= ∫(x = 0 to 1) (2/3) e^(3xy) {for y = 0 to 2} dx
Let C represent a parabolic arc from the point (3, -3, 2) to (4, 1, 5) and
F(x, y, z) = [x/(x^2 + y^2 + z^2)] i + [y/(x^2 + y^2 + z^2)] j + [z/(x^2 + y^2 + z^2)] k.
Given this information, evaluate
∫