5^x=125
Let's say I didn't know off the top of my head that 5^3=125, how would I set it up to solve x and get "3" ? Thanks!
Let's say I didn't know off the top of my head that 5^3=125, how would I set it up to solve x and get "3" ? Thanks!
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xlog5 =log125 so x= (log125)/(log5) =3...................method 1
5^X =5^3 equating powers x= 3................. method 2
5^X =5^3 equating powers x= 3................. method 2
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5^x=125 -->make 125 an exponential form, it should have the base same with the other side which is 5 so we could equate their exponents
125 is also 5^3 right? so 5^x = 5^3, now since they already both have the same bases, equate their exponents, x=3
125 is also 5^3 right? so 5^x = 5^3, now since they already both have the same bases, equate their exponents, x=3