Triangle ABC has vertices at the points A(-2,3),B(7,4)and C(5,22).What kind of triangle is Triangle ABC?
also Explain how-isosceles because not all sides are equal (causing it to not be an equilatera
Graph the following linear inequalities.
1. y5x + 2
2. y4x + 2
3. y3x + 2
4. y2x + 2
5. y3x + - 2
6. y5x- 3-Well its been more than 15 minutes but here are the answers.
These are all equations
i) Q(sqrt(11))/Q
ii) Q(sqrt(11),sqrt(5))/Q
iii) Q(sqrt(11),sqrt(5),sqrt(55))/Q-i) Since the minimal polynomial of √11 (which is x^2 - 11) is irreducible over Q and is of degree 2, we see that [Q(√11
i have 3 math problems but i dont understand how to solve them
1.) solve by factoring, 4x^2-x-3=0
2.) simplify, x^2-4/x^2-3x+2
3.)simplify, c^2/de * 7d^4e/4c
please explain how to do each problem
Always???
sometimes??
Maybe?-ALWAYS.A square is simply a rhombus with 90 degree angles.-Always. It has all the characteristics of a rhombus, plus having four right angles.
These were the only questions I got stuck on, thanks in advance!!!!! :D
1. What is the approximate circumference of a semicircle with a radius of 12 centimeters?
(Points : 1)18.8 centimeters
37.7 c
(a) Write the following in standard form:
(i) 156,700,000 = ………………………………………..
(ii) 0.000341 = …………………………………..….….. .. (1 mark)
(b) Write the following without standard form:
(i) 2.6 × 105 = …………………………
Multiply the first equation by 3:.... 15x + 12y = -18
Multiply the second equation by 2: 4x + 12y = 26
Subtract one from the other:
11x = -44
x = -4
Use this value in the first equation: 5(-4) + 4y =
Put (-3, -2), m=4 into slope intercept.
Full points for best answer! Thank you!-let y=mx + c where m is the gradient and c is the intercept
then using the co ordinates (-3,-2)
let -2= 4(-3) + c
the
1 and 2.
http://img135.imageshack.us/img135/4266/110609172102.png
3 and 4 and 5.
http://img193.imageshack.us/img193/4206/110609172112.png-You have 1 right. 2 is equilateral. 3 is none. 4 is regula
A particle moves on a circle of radius ...... Calc 3- velocity, motion, speed- 10 POINTS BEST ANSWER?
A particle moves on a circle of radius 6 cm, centered at the origin, in the xy-plane (x and y meas
x-3y=27
2x-y=9....pleassee-1) x-3y=27
2) 2x-y=9
3(2x-y)=27
3) x-3y=3(2x-y)
x-3y=6x-3y
x-6x=-3y+3y
-5x=0
x=0
4) x-3y=27
0-3y=27
y=27/(-3)=-9
5) So x=0 and y=-9-I found this on the internet
T