x-3y=27
2x-y=9....pleassee
2x-y=9....pleassee
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1) x-3y=27
2) 2x-y=9
<=> 3(2x-y)=27
3) x-3y=3(2x-y)
<=> x-3y=6x-3y
<=> x-6x=-3y+3y
<=> -5x=0
<=> x=0
4) x-3y=27
<=> 0-3y=27
<=> y=27/(-3)=-9
5) So x=0 and y=-9
2) 2x-y=9
<=> 3(2x-y)=27
3) x-3y=3(2x-y)
<=> x-3y=6x-3y
<=> x-6x=-3y+3y
<=> -5x=0
<=> x=0
4) x-3y=27
<=> 0-3y=27
<=> y=27/(-3)=-9
5) So x=0 and y=-9
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I found this on the internet
The link will be under the answer if you want to check it
x - 3y = 27
Multiplying with 2 we get,
2x - 6y = 54
2x - y = 9
(-) (+) (-)
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-5y = 45
therefore y = 45/(-5) = -9
x - 3y = 27
x - 3(-9)= 27
x + 27 = 27
therefore x = 27 - 27 = 0
The link will be under the answer if you want to check it
x - 3y = 27
Multiplying with 2 we get,
2x - 6y = 54
2x - y = 9
(-) (+) (-)
=============
-5y = 45
therefore y = 45/(-5) = -9
x - 3y = 27
x - 3(-9)= 27
x + 27 = 27
therefore x = 27 - 27 = 0
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i can only answer 1 question
2x-y=9
x=5
y=1
hope u find this useful :-)
2x-y=9
x=5
y=1
hope u find this useful :-)