From the equation of a parabola identify the focus, directrix, and axis of symmetry.
x = (-1/8)y^2
Thanks for your help!
x = (-1/8)y^2
Thanks for your help!
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Take the original equation and multiply -8 by both sides to get
-8x = y²
This is now the equation for a parabola
y² = 4px
Where p = -2.
The focus is (p,0), or (-2,0).
The directrix is x = -p, or x=2.
Because y is squared, the axis of symmetry is the x-axis.
Remember that if you are also supposed to graph this that it is a horizontal parabola that opens to the left and the vertex is at (0,0).
:)
-8x = y²
This is now the equation for a parabola
y² = 4px
Where p = -2.
The focus is (p,0), or (-2,0).
The directrix is x = -p, or x=2.
Because y is squared, the axis of symmetry is the x-axis.
Remember that if you are also supposed to graph this that it is a horizontal parabola that opens to the left and the vertex is at (0,0).
:)