Solve for x? 10x^7 (x+2) = 2x^2?

points goes to anyone who can help

10x^7(x+2) = 2x^2
10x^8 + 20x^7 - 2x^2 = 0
2x^2[5x^6 + 10x^5 - 1] = 0

Resorting to using a calculator, the 4 real values are
x = 0 (twice), 0.598754882813, -2.006154632568,
The other 4 solutions are two pairs of complex conjugates,
These are approximately
0.2190 + 0.5736 i
0.2190 - 0.5736 i
- 0.5153 + 0.4196 i
- 0.5153 - 0.4196 i

Regards - Ian H