When 0.514 g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 25.8 C to 29.4 C. Find ⌂E rxn for the combustion of biphenyl in kJ/mol biphenyl. The heat capacity of the bomb calorimeter, determined in a separate experiment, is 5.86 kJ/ C.
The answer is - 6.30 * 10^3 kJ/mol
how do I get there?
The answer is - 6.30 * 10^3 kJ/mol
how do I get there?
-
heat of combustion = heat capacity of calorimter x ∆T
Q = 5.86kJ/ºC x 3.6ºC = 21.096kJ
0.514g / 154g/mole = 0.00334moles
21.096kJ / 0.00334moles = 6.32x10^3kJ/mole
Q = 5.86kJ/ºC x 3.6ºC = 21.096kJ
0.514g / 154g/mole = 0.00334moles
21.096kJ / 0.00334moles = 6.32x10^3kJ/mole