When 0.514 g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature
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When 0.514 g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature

[From: ] [author: ] [Date: 12-10-13] [Hit: ]
The answer is - 6.how do I get there?Q = 5.86kJ/ºC x 3.6ºC = 21.0.......
When 0.514 g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 25.8 C to 29.4 C. Find ⌂E rxn for the combustion of biphenyl in kJ/mol biphenyl. The heat capacity of the bomb calorimeter, determined in a separate experiment, is 5.86 kJ/ C.



The answer is - 6.30 * 10^3 kJ/mol
how do I get there?

-
heat of combustion = heat capacity of calorimter x ∆T
Q = 5.86kJ/ºC x 3.6ºC = 21.096kJ

0.514g / 154g/mole = 0.00334moles

21.096kJ / 0.00334moles = 6.32x10^3kJ/mole
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