Show Average Velocity Over Interval
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Show Average Velocity Over Interval

[From: ] [author: ] [Date: 12-10-13] [Hit: ]
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Near the surface of the moon, the distance traveled by a falling object is given by the formula s(x) = (8t^2)/3, where t is measured in seconds in seconds, s(t) is in feet, and t = 0 corresponds to the instant that the object begins to fall.

Show that the average velocity over the interval [tsub1, tsub2] is given by
delta(s)/delta(t) = (8/3)(tsub2 + subt1)

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s(x) = distance in feet
t = time in seconds
velocity in feet/sec = d[s(x)]/dt
s(x) = (8t^2)/3
ds(x)/d(t) = 16t/3
Average velocity over interval = (1/2)*(8/3)*[tsub2 - tsub1]
= (4/3)*[tsub2 - tsub1]
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keywords: Over,Average,Interval,Show,Velocity,Show Average Velocity Over Interval
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