The height (feet) of a ball launched in the air t seconds after it is launched is given by:
-16t+208t+23
The velocity of the ball when at a height of 110 feet is __ ft/sec
-16t+208t+23
The velocity of the ball when at a height of 110 feet is __ ft/sec
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Okay, doing it again with correct equation.
When now find the value of t if y = 110 feet.
I can't really remember how to solve this in algebra, but if you use your graphing calculator, you will see that y=110 ft at about .433 seconds.
Next, find the derivative, which is a function of velocity:
y' = -31t +208
Using this function, solve for t=.433.
y' = -31(.433) + 208
You should get about 195 ft/sec.
When now find the value of t if y = 110 feet.
I can't really remember how to solve this in algebra, but if you use your graphing calculator, you will see that y=110 ft at about .433 seconds.
Next, find the derivative, which is a function of velocity:
y' = -31t +208
Using this function, solve for t=.433.
y' = -31(.433) + 208
You should get about 195 ft/sec.