Allele frequencies with Hardy-Weinberg
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Allele frequencies with Hardy-Weinberg

[From: ] [author: ] [Date: 12-10-07] [Hit: ]
and 0.01 of 10,000 is 100.So the answer is 100.......
The following questions refer to this information: In the year 2500, five male space colonists and five female space colonists from Earth settle on an uninhabited Earthlike planet in the Andromeda galaxy. The colonists and their offspring randomly mate for generations. All ten of the original colonists had free ear lobes, and two are heterozygous for that trait. The allele for free ear lobes is dominant to the allele for attached ear lobes.

I know A= 0.9 and a= 0.1, but how can I figure out this:
) If one assumes that Hardy-Weinberg equilibrium applies to the population of colonists on this planet, about how many people will have attached ear lobes when the planet's population reaches 10,000? 36) ______
A) 400 B) 10,000 C) 1,000 D) 800 E) 100

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When the population is 10, frequency of allele "a"/ q is equal to 0.1
And if hardy-weinberg law applies, there's no external disturbance affecting the population, and the allelic frequencies DO NOT CHANGE.

So, frequency of allele "a" will still be 0.1, and genotypic frequency (of recessives=attached ear lobes) will be q2 that is 0.1x0.1 = 0.01

and 0.01 of 10,000 is 100.

So the answer is 100.
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