How would you find the derivative of this problem
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How would you find the derivative of this problem

[From: ] [author: ] [Date: 12-10-02] [Hit: ]
http://25.media.tumblr.com/tumblr_mb8p96…-Chain rule,Can you take the derivative from here?1/2[1+cos^2(x)]^-1/2 (-sin(x)cos(x)) = -(Sin(x)Cos(x))/(2[1+cos^2(x)]^1/2)-The square root is the same as being to the power of 1/2.......
The square root throws me off...

http://25.media.tumblr.com/tumblr_mb8p96…

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Chain rule, you can rewrite that problem as:

[1+cos^2(x)]^1/2

Can you take the derivative from here?

1/2[1+cos^2(x)]^-1/2 (-sin(x)cos(x)) = -(Sin(x)Cos(x))/(2[1+cos^2(x)]^1/2)

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The square root is the same as being to the power of 1/2.

So we can rewrite that as:
(1 + cos^2(z))^(1/2)

And that becomes:

(1/2)(1 + cos^2(z))^(-1/2)
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