A car moving eastward along a straight road increases its speed uniformly from 16m/s to 32m/s in 10.0s. What is the car's average velocity?
Also, how far did the car move while accelating?
Thanks!
Also, how far did the car move while accelating?
Thanks!
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The average velocity is given by the formula, where V is velocity (Vinitial + Vfinal)/2
Therefore, (16+32)/2=24m/s east
To find the displacement of the car, we'll use the formula d=(1/2)at^2 +Vinitial*t, where a is acceleration and t is time.
Since we don't have acceleration, we have to find by doing (Vfinal-Vintial)/t
Therefore, (32-16)/10=2.4 m/(s*s), east
Back to the displacement, d= (1/2)(2.4)(10)^2 + (16)(10)
d= 120+160
d=280 m
Therefore, (16+32)/2=24m/s east
To find the displacement of the car, we'll use the formula d=(1/2)at^2 +Vinitial*t, where a is acceleration and t is time.
Since we don't have acceleration, we have to find by doing (Vfinal-Vintial)/t
Therefore, (32-16)/10=2.4 m/(s*s), east
Back to the displacement, d= (1/2)(2.4)(10)^2 + (16)(10)
d= 120+160
d=280 m