a couple has 3 children, find the probability that exactly 2 boys or 2 girls
I don't know how to figure this one out.. how is the answer 6/8? i would think 2/8 cause only possibility is GG and BB
I don't know how to figure this one out.. how is the answer 6/8? i would think 2/8 cause only possibility is GG and BB
-
There are 8 possible sequences of genders of the 3 children, one of which
is all girls and another of which is all boys. The rest have either 2 boys
and 1 girl or 1 boy and 2 girls. So the probability will be 6/8 = 3/4.
Edit: Writing out the 8 possible sequences, we have
GGG, GGB, GBG, GBB, BBB, BBG, BGB, BGG.
is all girls and another of which is all boys. The rest have either 2 boys
and 1 girl or 1 boy and 2 girls. So the probability will be 6/8 = 3/4.
Edit: Writing out the 8 possible sequences, we have
GGG, GGB, GBG, GBB, BBB, BBG, BGB, BGG.
-
The children are distinct, making more possibilities. Symbolically, you're dealing with an ordered triplet, rather than a multiset.
(G, G, G)
(G, G, B)
(G, B, G)
(G, B, B)
(B, B, B)
(B, B, G)
(B, G, B)
(B, G, G)
That's all 8 possibilities for the genders of the three children, youngest to oldest, 6 of which contain exactly two of the same gender.
(G, G, G)
(G, G, B)
(G, B, G)
(G, B, B)
(B, B, B)
(B, B, G)
(B, G, B)
(B, G, G)
That's all 8 possibilities for the genders of the three children, youngest to oldest, 6 of which contain exactly two of the same gender.
-
3 children... then the probability of (2 boys or 2 girls) is 1....
What you might be looking for is P(2 boys) or P(2girls)
SO
A....B...C
B....B....B
B....B....G
B....G....B
G....B....B
B....G....G
G....B....G
G....G....B
G....G....G
are all the possibilities
So, 8 possibilities...
Of these, 3 have two boys, and 3 have 2 girls That's 6
So (P(2 boys) or P(2 girls)) = (3/8 + 3/8) = 6/8
What you might be looking for is P(2 boys) or P(2girls)
SO
A....B...C
B....B....B
B....B....G
B....G....B
G....B....B
B....G....G
G....B....G
G....G....B
G....G....G
are all the possibilities
So, 8 possibilities...
Of these, 3 have two boys, and 3 have 2 girls That's 6
So (P(2 boys) or P(2 girls)) = (3/8 + 3/8) = 6/8
-
Nope, think again..........
GGG
GGB
GBG
GBB
BBB
BBG
BGB
BGG
Out of these 8 possibilities, all but 2 have either 2 boys or 2 girls, leaving 6 that meet the test.
The probability of exactly 2 boys OR 2 girls is 6/8 = 3/4 = 75% = 0.75
GGG
GGB
GBG
GBB
BBB
BBG
BGB
BGG
Out of these 8 possibilities, all but 2 have either 2 boys or 2 girls, leaving 6 that meet the test.
The probability of exactly 2 boys OR 2 girls is 6/8 = 3/4 = 75% = 0.75
-
The law of probability cannot be used in procreation unless one looks at both parents Family Tree/Ancestry.
The gender of the 3 existing children is a clue, but not an absolute.
.
The gender of the 3 existing children is a clue, but not an absolute.
.
-
THREE children
GGG
GGB
GBG
BGG
BBG
BGB
BBG
BBB
Only all boys or all girls does not meet the definition
GGG
GGB
GBG
BGG
BBG
BGB
BBG
BBB
Only all boys or all girls does not meet the definition