A density function: Probability (Calc II)
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A density function: Probability (Calc II)

[From: ] [author: ] [Date: 13-09-28] [Hit: ]
6).on the interval (0,1) must be 1,since the integral is 1.......
a density function f(x) = C(2-x^2) for [0-1]. I have found the constant C to make the function's parameters equal to 1. C = 0.6. now it is asking me to find a formula and graph the function and then find its mean density.. The whole function must equal 100%. I do not understand where to begin! Please help!!!

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I agree with you that the integral from 0 to 1 of
0.6(2-x^2) dx is
[1.2x - 0.2x^3] at x=1
= 1.
The graph is a simple parabola
with its peak at (1.2,0) and you
can pick a few x-values between
0 and 1 to make a smooth curve
down to (1,0.6).
The mean value of the density function
on the interval (0,1) must be 1,
since the integral is 1.
1
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