Concentration of solution problem
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Concentration of solution problem

[From: ] [author: ] [Date: 13-09-28] [Hit: ]
Therefore the AgNO3 solution contained 0.Molar mass Ag = 107.mol Ag = 0.250/107.87 = 0.You had 0.......
75 ml of AgNO3 solution react with enough Cu to produce 0.250 g of Ag by single displacement. what is molarity of the initial AgNO3 solution if Cu(NO3)2 is the other product?

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You produced 0.250g Ag metal
Therefore the AgNO3 solution contained 0.250g Ag
Molar mass Ag = 107.87g/mol
mol Ag = 0.250/107.87 = 0.00232 mol Ag
1mol Ag will produce 1 mol AgNO3
You had 0.00232 mol AgNO3 in the 75mL solution .
Mol of AgNO3 in 1000mL solution = 1000/75*0.00232 = 0.0309 mol AgNO3 /L

Molarity of AgNO3 solution = 0.0309M
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