A stone thrown horizontally from the top of a 28-m tower hits the ground at a point 25 m from the base of the

A stone thrown horizontally from the top of a 28-m tower hits the ground at a point 25 m from the base of the tower. (Ignore any effects due to air resistance.)

(a) Find the speed at which the stone was thrown. Vo= 10.45m/s

(b) Find the speed of the stone just before it hits the ground. Vo=

t = √(2h/g)

t = √(2 • 28/9.81)

t = 2.39 second.

v = d/t

v→ = 25/2.38

v→ = 10.5 m/s

v↓ = at

v↓ = 9.81 • 2.39

v↓ = 23.4 m/s

v = √(v→ ² v↓²)

v = √(10.5 ² 23.4²)

v = √(110 548)

v = √658

v = 25.6 m/s

The answer is limited in the number of significant digits to two. I gave a bonus digit because I know no one will like a two digit answer.

ive been answering questions for the past few hours but my brain is tired so ill answer you later.

just dont forget to give me the 10 points just in case i forget to return