Balance the reaction for the combustion of propane:
?C3H8+?O2→?CO2+?H2O
everywhere the is a ? a coefficient goes there
I put 4,2,4,2 but i was wrong.
?C3H8+?O2→?CO2+?H2O
everywhere the is a ? a coefficient goes there
I put 4,2,4,2 but i was wrong.
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C3H8 + O2→ CO2 + H2O
Remember that it usually helps to balance oxygen last.
Start by tripling the amount of CO2, to give 3 carbons on each side
C3H8 + O2→ 3CO2 + H2O
Quadruple the amount of H2O, to give 8 hydrogens on each side
C3H8 + O2→ 3CO2 + 4H2O
Counting up the amount of oxygens, you have 2 on the left, and 10 on the right.
Multiply the amount of O2 by 5, to give you 10 oxygen on each side
C3H8 + 5O2→ 3CO2 + 4H2O
Remember that it usually helps to balance oxygen last.
Start by tripling the amount of CO2, to give 3 carbons on each side
C3H8 + O2→ 3CO2 + H2O
Quadruple the amount of H2O, to give 8 hydrogens on each side
C3H8 + O2→ 3CO2 + 4H2O
Counting up the amount of oxygens, you have 2 on the left, and 10 on the right.
Multiply the amount of O2 by 5, to give you 10 oxygen on each side
C3H8 + 5O2→ 3CO2 + 4H2O
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C3H8 + 5O2 → 3CO2 + 4H2O
Generally you can balance these by inspection, but for a systematic approach, see:
http://www.nyu.edu/classes/tuckerman/adv…
Generally you can balance these by inspection, but for a systematic approach, see:
http://www.nyu.edu/classes/tuckerman/adv…