Help with this equation: √(12+√(12+√(12…)=x. Find the value of x.

Please answer this equation with steps involved to solve it.

Squaring the given we get
12+sqrt(12+sqrt(12+sqrt(12...))) = x^2
12 + x = x^2 [BECAUSE sqrt(12+sqrt(12+sqrt(12...))) = x as given in your question ]
then solving the above quadratic
x^2 - x -12 = 0
x^2 - 4x + 3x - 12 = 0
x(x-4) + 3(x-4) = 0
(x-4)(x+3) = 0
x = 4 or x = -3
But the value of the given expression is positive, so ignoring x = - 3
ANS IS x = 4

sqrt12+ (sqrt12+-------------------) = x
or sqrt(12 + x )= x
or 12+ x = x^2
or x^ - x - 12 = 0
( x- 4 ) ( x+ 3 ) =0
so x= 4 & x= - 3 ANSWER

Rameshwa is correct, except that by convention √a is a positive number.
So x=4.

x
= √(12+√(12+√(12…)
= 3.991546.....