Tangent / Secant Line Calculus Problem
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Tangent / Secant Line Calculus Problem

[From: ] [author: ] [Date: 13-09-25] [Hit: ]
If x=05 then the slope equals : ?Thank you-P(1,91) and Q(x,If thats x = 5,If its another value of x, just plug it in to 82(x+1)-Youre welcome!......
The point P(191) lies on the curve y=82 x^2+9
(a) If Q is the point (x,82 x^2+9), use your calculator to find the slope of the secant line PQ (correct to six decimal places) for the following values of x.

If x=05 then the slope equals : ?

Thank you

-
P(1,91) and Q(x, 82x²+9)
Slope of PQ:
(82x²+9 - 91) / (x-1)
= (82x² - 82) / (x-1)
= (82(x-1)(x+1)) / (x-1)
= 82(x+1)

If that's x = 5, then the slope is 82(5+1) = 492
If it's another value of x, just plug it in to 82(x+1)

-
You're welcome!

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keywords: Tangent,Problem,Secant,Line,Calculus,Tangent / Secant Line Calculus Problem
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