Hello if anyone could help me with this that'd be so awesome thank you so much!
i've been trying for ever and keep getting it wrong or writing it in wrong notation
Find the Domain for f(x)= \sqrt[4]{x^2 - 8 x}
thank you for any help!
i've been trying for ever and keep getting it wrong or writing it in wrong notation
Find the Domain for f(x)= \sqrt[4]{x^2 - 8 x}
thank you for any help!
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I'm assuming that you are working with real numbers and so you cannot let the value in the square root become less than zero. So x can be anything such that
x^2 - 8x >= 0
divide by x on both sides and get
x - 8 >= 0
add 8 to both sides and get
x >= 8
So your domain is everything greater than or equal to 8.
x^2 - 8x >= 0
divide by x on both sides and get
x - 8 >= 0
add 8 to both sides and get
x >= 8
So your domain is everything greater than or equal to 8.
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substitute the variables then perform the order of operations pemdas