Parallel lines math question

Find the value of k such that the lines with equations
3x + 2y - 4 = 0 and kx - 3y + 8 = 0 are parallel.

I'm having trouble with this problem. i know that parallel lines have the same slope so based on 3x+2y-4=0 the slope would be -3/2x what i can't figure out is how to find the value of k using the slope that i alreadyy have.

Thanks in advance to anyone who'll answer ^^

Make y the subject in each equation:

y = -3x/2 + 2
y = kx/3 - 8/3

As the slopes of parallel lines are equal, set the slopes (the coefficients of the x terms) to equal each other:

k/3 = -3/2
k = -9/2

kx - 3y + 8 = 0
So
3y = kx + 8
y = (k/3)x + 8/3

You want k/3 to have the value -3/2, so k has to be . . . . .