Maths help involving 'interpreting linear relationships'
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Maths help involving 'interpreting linear relationships'

[From: ] [author: ] [Date: 13-07-20] [Hit: ]
youll get the slope and whatever value you have for the numerator is the rise and the denominator is the run.You pick any two points on the graph. Lets assume the two points on the graph have (5,6) (3,4). 5 is x1 ; 3 is x2 ; 6 is y1; and 4 is y2.......
i kno gradient, but i dont get the difference between the gradient formula y2-y1 x2-x1 & just finding 2 points on the graph to determine rise/run

General maths yr 11

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the gradient formula is technically the same as finding two points on the graph. Lets say your two coordinates are A (2,4) and B(10,5) on a straight line
rise/run would be the same as y2-y1 / x2-x1
so to find the gradient 5-4 / 10-2
= 1/8
Though i guess the formula is just there to help you :D

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Pick two points and plug those into y2-y1 x2-x1 equation. After you solve it, you'll get the slope and whatever value you have for the numerator is the rise and the denominator is the run.

You pick any two points on the graph. Lets assume the two points on the graph have (5,6) (3,4). 5 is x1 ; 3 is x2 ; 6 is y1; and 4 is y2. Solve the equation and u get the slope or rise/run
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