MATH HELP PLEASE 10 points

The one-to-one functions and are defined as follows.
g= (7,1) (-1,-6) (0,8) (1,-1)
h(x)= 4x+3

Find the following please,

g^-1(-1) =
h^-1(x)=
(h^-1 *open circle* h) (-2) =

thanks!!1

Hi,

The one-to-one functions and are defined as follows.
g= (7,1) (-1,-6) (0,8) (1,-1)
h(x)= 4x+3

Find the following please,

g^-1(-1) = 1 <==ANSWER

When the y value is -1 then its given x value was 1.


h^-1(x) = - 1<==ANSWER

For h^-1(x), 4x + 3 = x

-3x = 3

x = -1


(h^-1 ο h) (-2) = -2 <==ANSWER H^-1 and h are opposites so this gives the original value back.

I hope that helps!! :-)

a) since g(1) = -1, that means
g^-1(-1) = 1

b)if y = h^-1(x), then
x = 4y+3
4y=x-3
y=(x-3)/4
h^-1(x) = (x-3)/4

b) h^-1 composed with h is the identity mapping, so we get
(h^-1 *open circle* h) (-2) = -2

-6
1/4x+3
-5