I'm going to ask my teacher after class, so don't think I'm lazy, but I just want to have a backup answer just in case she confuses me even more and I end up just nodding my head like I understand when I really don't.
Find the exact values of s in the interval [0,2π) that satisfy the given conditions cos²s = 1/4
s=?
I just need the answers to the question, however, I'd greatly appreciate it if someone gave me a simple show of work without leaving anything important out so that I can fully understand this for future reference.
Find the exact values of s in the interval [0,2π) that satisfy the given conditions cos²s = 1/4
s=?
I just need the answers to the question, however, I'd greatly appreciate it if someone gave me a simple show of work without leaving anything important out so that I can fully understand this for future reference.
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If the square is 1/4, then basically cos x = ±1/2.
If you know your 30-60-90 triangle proportions, you should be able to get it.
s = 60 degrees = π/3 is one value
2π/3, 4π/3 and 5π/3 are the others.
If you know your 30-60-90 triangle proportions, you should be able to get it.
s = 60 degrees = π/3 is one value
2π/3, 4π/3 and 5π/3 are the others.
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As cos²s = 1/4, therefore cos(s)=+1/2 or -1/2.
So, s=π/3. 2π/3, 4π/3, 5π/3.
We learn the values: cos0=1, cosπ/6=V3/2, cosπ/4=1/V2, cosπ/3=1/2, cosπ=0
i hope you got it.
So, s=π/3. 2π/3, 4π/3, 5π/3.
We learn the values: cos0=1, cosπ/6=V3/2, cosπ/4=1/V2, cosπ/3=1/2, cosπ=0
i hope you got it.
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Sure, no problem.
cos²s = ¼
cos s = ±√¼ = ±½
s = π/3, 2π/3, 4π/3, 5π3
cos²s = ¼
cos s = ±√¼ = ±½
s = π/3, 2π/3, 4π/3, 5π3