Antiderivative of (x^2)^5
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Antiderivative of (x^2)^5

[From: ] [author: ] [Date: 13-03-05] [Hit: ]
x^10,(x^10+1)/(10+1)+C,x^11/11+C.Answer: x^11/11+C.......
You simplify the expression by multiplying e ponents. Then you take antiderivative a.k.a integral. Which is the opposite opperation of taking a derivative. So add 1 to exponent then divide expression by the new exponent. Therefore ...

Antiderivative of (x+2)^5 or x^10
Will be (x^11)/11

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Remember the formula.
x^n dx=(x^n+1)/(n+1)+C,
(x^2)^5,
x^2*5,
x^10,
(x^10+1)/(10+1)+C,
x^11/11+C.
Answer: x^11/11+C.

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antiderivative of (x^2)^5 =
antiderivative of x^10 =
x^11/11 + c

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(x^11)/11 +c where c is a constant
1
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